International
Tables for
Crystallography
Volume B
Reciprocal space
Edited by U. Shmueli

International Tables for Crystallography (2006). Vol. B. ch. 5.2, p. 554   | 1 | 2 |

Section 5.2.9. Translational invariance

A. F. Moodie,a J. M. Cowleyb and P. Goodmanc

a Department of Applied Physics, Royal Melbourne Institute of Technology, 124 La Trobe Street, Melbourne, Victoria 3000, Australia,bArizona State University, Box 871504, Department of Physics and Astronomy, Tempe, AZ 85287-1504, USA, and cSchool of Physics, University of Melbourne, Parkville, Australia 3052

5.2.9. Translational invariance

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An important result deriving from Bethe's initial analysis, and not made explicit in the preceding formulations, is that the fundamental symmetry of a crystal, namely translational invariance, by itself imposes a specific form on wavefunctions satisfying Schrödinger's equation.

Suppose that, in a one-dimensional description, the potential in a Hamiltonian [{\bf H}_{t}(x)] is periodic, with period t. Then, [\varphi (x + t) = \varphi (x)] and [{\bf H}_{t}\psi (x) = {\bf E}\psi (x).] Now define a translation operator [\boldGamma f(x) = f(x + t),] for arbitrary [f(x)]. Then, since [\boldGamma \varphi (x) = \varphi (x)], and [\nabla^{2}] is invariant under translation, [\boldGamma {\bf H}_{t}(x) = {\bf H}_{t}(x)] and [\boldGamma {\bf H}_{t}(x)\psi (x) = {\bf H}_{t}(x + t)\psi (x + t) = {\bf H}_{t}(x) \boldGamma \psi (x).]

Thus, the translation operator and the Hamiltonian commute, and therefore have the same eigenfunctions (but not of course the same eigenvalues), i.e. [\boldGamma \psi (x) = \alpha \psi (x).] This is a simpler equation to deal with than that involving the Hamiltonian, since raising the operator to an arbitrary power simply increments the argument [\boldGamma^{m} \psi (x) = \psi (x + mt) = \alpha^{m} \psi (x).] But [\psi (x)] is bounded over the entire range of its argument, positive and negative, so that [|\alpha| = 1], and [\alpha] must be of the form [\exp\{i2\pi kt\}].

Thus, [\psi (x + t) = \boldGamma \psi (x) = \exp \{i2\pi kt\}\psi (x)], for which the solution is [\psi (x) = \exp \{i2\pi kt\} q(x)] with [q(x + t) = q(x)].

This is the result derived independently by Bethe and Bloch. Functions of this form constitute bases for the translation group, and are generally known as Bloch functions. When extended in a direct fashion into three dimensions, functions of this form ultimately embody the symmetries of the Bravais lattice; i.e. Bloch functions are the irreducible representations of the translational component of the space group.








































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